本文主要介绍了sqlserver rank() 排名函数的使用，具体如下：
-- 例子表数据 select * from test; -- 统计分数 select name,sum(achievement) achievement from test group by name; -- 按统计分数做排行 select rank() over( order by sum(achievement) desc) 排行,name,sum(achievement) achievement from test group by name;
求助问答存储过程使用：
use [db]
go
/****** object: storedprocedure [dbo].[sp_todayjoinuser] script date: 2021/1/26 14:45:24 ******/
set ansi_nulls on
go
set quoted_identifier on
go
-- =============================================
-- author: _hey_jude
-- create date: 2021-01-26
-- description: 获取今日发表帮助/回复的新用户
-- =============================================
create procedure [dbo].[sp_todayjoinuser]
@tablelevel int,
@date varchar(30)
as
declare @sql nvarchar(max)
declare @mintabid int
declare @maxtabid int
declare @maxf_id int
declare @helptablename nvarchar(max)
declare @tablecount int
begin
--最小f_id所在表
set @mintabid=0
set @tablecount=@mintabid
--最大f_id所在表
set @maxf_id=(select max(f_id) from [table] where f_isdelete=0)
set @maxtabid=@maxf_id/@tablelevel
set @helptablename='select userid, max([f_datetime]) as dt from [table] group by userid'
while @tablecount<=@maxtabid
begin
print @tablecount
set @helptablename += ' union select userid, max([datetime]) as dt from subtable'+cast(@tablecount as nvarchar(10))+' group by userid '
set @tablecount=@tablecount+1
end
set @sql='select [nikename] from (
select userid, rank() over(partition by userid order by dt) as num,dt from ( '+@helptablename+' ) as t ) as newt
left join [usertable] a with(nolock) on newt.userid = a.userid where num = 1 and dt > '''+@date+''''
exec sp_executesql @sql
end
go
partition的意思是对数据进行分区，sql语句如下
select* from (
select
row_number() over(partition by [姓名] order by [打卡时间] desc) as rownum,
[姓名],
[打卡时间]
from [dbo].[打卡记录表]
) temp
where temp.rownum = 1
通过 partition by [姓名] order by [打卡时间] desc，这句就可以做到，让数据按照姓名分组，并且在每组内部按照时间进行排序
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