JVM探秘6--图解虚拟机栈的局部变量表和操作数栈工作流程

2023-02-14,,,,

案例代码如下:

 public class JVMTest {
public static Integer num = 10; public int add(int i){
int j = 5;
int k = i+j;
j++;
k = num + j;
return k;
} public static void main(String[] args){
System.out.println(new JVMTest().add(4));
}
}

编译之后主要指令集如下:

 {
public static java.lang.Integer num;
descriptor: Ljava/lang/Integer;
flags: ACC_PUBLIC, ACC_STATIC public com.lucky.grpc.JVMTest();
descriptor: ()V
flags: ACC_PUBLIC
Code:
stack=1, locals=1, args_size=1
0: aload_0
1: invokespecial #1 // Method java/lang/Object."<init>":()V
4: return
LineNumberTable:
line 3: 0 public int add(int);
descriptor: (I)I
flags: ACC_PUBLIC
Code:
stack=2, locals=4, args_size=2
0: iconst_5
1: istore_2
2: iload_1
3: iload_2
4: iadd
5: istore_3
6: iinc 2, 1
9: getstatic #2 // Field num:Ljava/lang/Integer;
12: invokevirtual #3 // Method java/lang/Integer.intValue:()I
15: iload_2
16: iadd
17: istore_3
18: iload_3
19: ireturn
LineNumberTable:
line 7: 0
line 8: 2
line 9: 6
line 10: 9
line 11: 18
public static void main(java.lang.String[]);
descriptor: ([Ljava/lang/String;)V
flags: ACC_PUBLIC, ACC_STATIC
Code:
stack=3, locals=1, args_size=1
0: getstatic #4 // Field java/lang/System.out:Ljava/io/PrintStream;
3: new #5 // class com/lucky/grpc/JVMTest
6: dup
7: invokespecial #6 // Method "<init>":()V
10: iconst_4
11: invokevirtual #7 // Method add:(I)I
14: invokevirtual #8 // Method java/io/PrintStream.println:(I)V
17: return
LineNumberTable:
line 15: 0
line 16: 17 static {};
descriptor: ()V
flags: ACC_STATIC
Code:
stack=1, locals=0, args_size=0
0: bipush 10
2: invokestatic #9 // Method java/lang/Integer.valueOf:(I)Ljava/lang/Integer;
5: putstatic #2 // Field num:Ljava/lang/Integer;
8: return
LineNumberTable:
line 4: 0
}

其中第17行到第41行是add方法的指令,接下来就一行一行图解虚拟机栈是如何执行的!

第一步:iconst_5  :将int类型的常量5压入操作数栈

第二步:istore_2 :将操作数栈顶中int类型数据放入局部常量表下标为2的位置,从0开始数也就是第三个位置

第三步:iload_1 :

JVM探秘6--图解虚拟机栈的局部变量表和操作数栈工作流程的相关教程结束。

《JVM探秘6--图解虚拟机栈的局部变量表和操作数栈工作流程.doc》

下载本文的Word格式文档,以方便收藏与打印。