Java异常处理中finally中的return会覆盖catch语句中的return语句和throw语句，所以Java不建议在finally中使用return语句
此外 finally中的throw语句也会覆盖catch语句中的return语句和throw语句
程序实例如下：（本代码来源于CSDN某大神：http://blog.csdn.net/hguisu/article/details/6155636 在此表示感谢）
package Test;
public class TestException {
public TestException() {
}
boolean testEx() throws Exception {
boolean ret = true;
try {
ret = testEx1();
} catch (Exception e) {
System.out.println("testEx, catch exception");
ret = false;
throw e;
} finally {
System.out.println("testEx, finally; return value=" + ret);
return ret;
}
}
boolean testEx1() throws Exception {
boolean ret = true;
try {
ret = testEx2();
if (!ret) {
return false;
}
System.out.println("testEx1, at the end of try");
return ret;
} catch (Exception e) {
System.out.println("testEx1, catch exception");
ret = false;
throw e;
} finally {
System.out.println("testEx1, finally; return value=" + ret);
return ret;
}
}
boolean testEx2() throws Exception {
boolean ret = true;
try {
int b = 12;
int c;
for (int i = 2; i >= -2; i--) {
c = b / i;
System.out.println("i=" + i);
}
return true;
} catch (Exception e) {
System.out.println("testEx2, catch exception");
ret = false;
throw e;
} finally {
System.out.println("testEx2, finally; return value=" + ret);
return ret;
}
}
public static void main(String[] args) {
TestException testException1 = new TestException();
try {
testException1.testEx();
} catch (Exception e) {
e.printStackTrace();
}
}
}
输出结果为：
i=2
i=1
testEx2, catch exception
testEx2, finally; return value=false
testEx1, finally; return value=false
testEx, finally; return value=false
此外：
finally块的语句在try或catch中的return语句执行之后返回之前执行且finally里的修改语句不能影响try或catch中 return已经确定的返回值（如果catch语句中返回的是一个引用，那么在finally语句中对引用的内容进行修改是会影响catch中return的返回值的），若finally里也有return语句则覆盖try或catch中的return语句直接返回。
