AC自动机模板题 HDU - 2222

2023-04-24,,

Keywords Search  HDU - 2222

贴个vj的链接https://vjudge.net/problem/HDU-2222

题意:T组数据,n个单词,再给你一个串,看有几个单词在这个串里面出现过

Sample Input

1
5
she
he
say
shr
her
yasherhs

Sample Output

3

#include <bits/stdc++.h>
#define ll long long
#define ull unsigned long long
using namespace std; const int inf = 0x3f3f3f3f;
const ll INF = 0x3f3f3f3f3f3f3f3f; const int N = 5e5 + 1000;
int fa[N], trie[N][30], tot, vis[N]; void build(string s){
int len = s.size();
int pos = 0;
for(int i = 0; i < len; i++){
int son = s[i] - 'a';
if(!trie[pos][son]) trie[pos][son] = ++tot;
pos = trie[pos][son];
}
vis[pos]++;
}
void getfail(){
queue<int> q;
for(int i = 0, p; i < 26; i++){
p = trie[0][i];
if(p){
fa[p] = 0;
q.push(p);
}
}
while(q.size()){
int now = q.front();
q.pop();
for(int i = 0; i < 26; i++){
int u = trie[now][i];
if(u){
q.push(u);
fa[u] = trie[fa[now]][i];
}
else trie[now][i] = trie[fa[now]][i];
}
}
} int getans(string s){
int now = 0, ans = 0;
for(int i = 0; i < s.size(); i++){
now = trie[now][s[i]-'a'];
for(int j = now; j && vis[j]!=-1; j = fa[j]){
ans+=vis[j];
vis[j] = -1;
}
}
return ans;
} int main(){
int t; cin >> t;
fa[0] = 0;
while(t--){
memset(trie, 0, sizeof(trie));
memset(vis, 0, sizeof(vis));
tot = 0;
int n; cin >> n;
string s;
for(int i = 1; i <= n; i++){
cin >> s;
build(s);
}
getfail();
cin >> s;
cout << getans(s) << endl;
}
}

AC自动机模板题 HDU - 2222的相关教程结束。

《AC自动机模板题 HDU - 2222.doc》

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