多线程面试题之【三线程按顺序交替打印ABC的方法】

2023-07-29,,

建立三个线程,线程名字分别为:A、B、C,要求三个线程分别打印自己的线程名字,但是要求三个线程同时运行,并且实现交替打印,即按照ABCABCABC的顺序打印。打印10轮,打印完毕控制台输出字符串:"打印完毕"

方法之一:使用Condition等待唤醒机制,代码如下:

import java.util.concurrent.CountDownLatch;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock; /**
* Created by gan on 2019/5/19 10:54.
*/
public class ConditionDemo { private static int num = 1; //打印“谁”标识符 private static Lock lock = new ReentrantLock();
private static final Condition conditionA = lock.newCondition();
private static final Condition conditionB = lock.newCondition();
private static final Condition conditionC = lock.newCondition(); private static CountDownLatch countDownLatch = new CountDownLatch(10); //使用闭锁计数器 public static void main(String[] args) throws Exception { long loop = countDownLatch.getCount(); //初始化打印轮数 new Thread(() -> {
for (int i = 1; i <= loop; i++) {
try {
printA();
} catch (InterruptedException e) {
}
}
}, "A").start(); new Thread(() -> {
for (int i = 1; i <= loop; i++) {
try {
printB();
} catch (InterruptedException e) {
}
}
}, "B").start(); new Thread(() -> {
for (int i = 1; i <= loop; i++) {
try {
printC(i);
} catch (InterruptedException e) {
}
}
}, "C").start(); countDownLatch.await(); System.out.println("打印完毕.........");
} //打印‘A’的方法
public static void printA() throws InterruptedException {
lock.lock();
if (num != 1) { //标识符等于1的时候打印A
conditionA.await();
}
System.out.print(Thread.currentThread().getName());
num = 2;
conditionB.signal();
lock.unlock();
} //打印‘B’的方法
public static void printB() throws InterruptedException {
lock.lock();
if (num != 2) { //标识符等于2的时候打印B
conditionB.await();
}
System.out.print(Thread.currentThread().getName());
num = 3;
conditionC.signal();
lock.unlock();
} //打印‘C’的方法
public static void printC(int loop) throws InterruptedException {
lock.lock();
if (num != 3) { //标识符等于3的时候打印A
conditionC.await();
}
System.out.print(Thread.currentThread().getName());
System.out.print("[" + loop + "]"); //轮数间隔符号
num = 1;
conditionA.signal();
countDownLatch.countDown();
lock.unlock();
} } 运行结果如下:

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