九度 1550 分糖果

题目

代码

#include <iostream>
#include <stdio.h>
using namespace std;

int candys[100010];
int left1[100010];
int right1[100010];

int main() {
    //freopen("testcase.txt", "r", stdin);
    int n;
    while(scanf("%d", &n) != EOF) {
        for(int i = 0; i < n; i ++) {
            scanf("%d", &candys[i]);
        }

        left1[0] = 1;
        for(int i = 1; i < n; i ++) {
            if(candys[i] > candys[i-1])
                left1[i] = left1[i-1] +1;
            else
                left1[i] = 1;
        }

        right1[n-1] = 1;
        for(int i = n-2; i >= 0; i--) {
            if(candys[i] > candys[i+1])
                right1[i] = right1[i+1] +1;
            else
                right1[i] = 1;
        }

        int maxVal = 0;
        for(int i = 0; i < n; i ++) {
            maxVal += max(left1[i], right1[i]);
        }
        printf("%d\n", maxVal);
    }
    return 0;
}