php实现统计网站在线人数的方法

2019-11-16,,,,,

本文实例讲述了php实现统计网站在线人数的方法。分享给大家供大家参考。具体实现方法如下:

<?php
function getIpAddress() { // 取得当前用户的IP地址
 if (getenv('HTTP_CLIENT_IP')) {
 $ip = getenv('HTTP_CLIENT_IP');
 } elseif (getenv('HTTP_X_FORWARDED_FOR')) {
 $ip = getenv('HTTP_X_FORWARDED_FOR');
 } elseif (getenv('REMOTE_ADDR')) {
 $ip = getenv('REMOTE_ADDR');
 } else {
 $ip = $_SERVER['REMOE_ADDR'];
 } 
 return $ip;
} 
function writeover($filename,$data,$method = 'w',$chmod = 0){
 $handle = fopen($filename, $method);
 !handle && die("文件打开失败");
 flock($handle, LOCK_EX);
 fwrite($handle, $data);
 flock($handle, LOCK_UN);
 fclose($handle);
 $chmod && @chmod($filename, 0777);
} 
function count_online_num($time, $ip) {
 $fileCount = './count.txt';
 $count = 0;
 $gap = 900; //15分钟不刷新页面就
 if (!file_exists($fileCount)) {
 $str = $time . "\t" . $ip . "\r\n";
 writeover($fileCount, $str, 'w', 1);
 $count = 1;
 } else {
 $arr = file($fileCount);
 $flag = 0;
 foreach($arr as $key => $val) {
  $val= trim($val);
  if ($val != "") {
  list($when, $seti) = explode("\t", $val);
  if ($seti ==$ip) {
   $arr[$key] = $time . "\t" . $seti;
   $flag = 1;
  } else {
   $currentTime = time();
   if ($currentTime - $when > 900) {
   unset($arr[$key]);
   }else{
   $arr[$key]=$val;
   }
  } 
  } 
 } 
 if ($flag == 0) {
  array_push($arr, $time . "\t" . $ip);
 } 
 $count = count($arr);
 $str = implode("\r\n", $arr);
 $str.="\r\n";
 writeover($fileCount, $str, 'w', 0);
 unset($arr);
 } 
 return $count;
} 
$time = time();
$ip = getIpAddress();
$online_num = count_online_num($time,$ip);
echo $online_num;
?>

希望本文所述对大家的php程序设计有所帮助。

《php实现统计网站在线人数的方法.doc》

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